(x^2-x-6)/(2x^2+9x-5)

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Solution for (x^2-x-6)/(2x^2+9x-5) equation:


D( x )

2*x^2+9*x-5 = 0

2*x^2+9*x-5 = 0

2*x^2+9*x-5 = 0

2*x^2+9*x-5 = 0

DELTA = 9^2-(-5*2*4)

DELTA = 121

DELTA > 0

x = (121^(1/2)-9)/(2*2) or x = (-121^(1/2)-9)/(2*2)

x = 1/2 or x = -5

x in (-oo:-5) U (-5:1/2) U (1/2:+oo)

(x^2-x-6)/(2*x^2+9*x-5) = 0

x^2-x-6 = 0

x^2-x-6 = 0

DELTA = (-1)^2-(-6*1*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+1)/(1*2) or x = (1-25^(1/2))/(1*2)

x = 3 or x = -2

(x+2)*(x-3) = 0

2*x^2+9*x-5 = 0

2*x^2+9*x-5 = 0

DELTA = 9^2-(-5*2*4)

DELTA = 121

DELTA > 0

x = (121^(1/2)-9)/(2*2) or x = (-121^(1/2)-9)/(2*2)

x = 1/2 or x = -5

(x+5)*(x-1/2) = 0

((x+2)*(x-3))/((x+5)*(x-1/2)) = 0

( x+2 )

x+2 = 0 // - 2

x = -2

( x-3 )

x-3 = 0 // + 3

x = 3

x in { -2, 3 }

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